Escape Velocity Calculator
Calculate the escape velocity and surface gravity of a planet, moon or star from its mass and radius.
How to use this calculator
- 1Pick a body from the list, or choose Custom to enter your own mass and radius.
- 2Read escape velocity in km/s, alongside surface gravity relative to Earth.
- 3Note that escape velocity does not depend on what is escaping — only on the body it is escaping from.
How the calculation works
v_escape = √(2GM ÷ r) v_orbit = √(GM ÷ r) g = GM ÷ r²- G
- Gravitational constant, 6.6743 × 10⁻¹¹ m³/(kg·s²)
- M
- Mass of the body being escaped
- r
- Distance from its centre — the radius, at the surface
Escape velocity comes from equating kinetic energy with gravitational potential energy: ½mv² = GMm/r. The escaping object's mass m appears on both sides and cancels, which is why escape velocity is the same for a pebble and a spacecraft.
Orbital velocity is escape velocity divided by √2, a relationship that holds for any body. Escaping needs exactly twice the kinetic energy of circling.
G is the least precisely known fundamental constant — CODATA 2018 gives a relative uncertainty of 2.2 × 10⁻⁵, far worse than the exact values for c and the Planck constant. Results here are therefore meaningful to about five significant figures at best.
Worked example
Escape velocity from Earth
- 1.Earth: M = 5.972 × 10²⁴ kg, equatorial r = 6.3781 × 10⁶ m, G = 6.6743 × 10⁻¹¹.
- 2.GM = 6.6743 × 10⁻¹¹ × 5.972 × 10²⁴ = 3.98589 × 10¹⁴.
- 3.2GM ÷ r = 2 × 3.98589 × 10¹⁴ ÷ 6.3781 × 10⁶ = 1.24987 × 10⁸.
- 4.v = √(1.24987 × 10⁸) = 11,180 m/s, or 11.18 km/s.
- 5.Surface gravity: GM ÷ r² = 3.98589 × 10¹⁴ ÷ (6.3781 × 10⁶)² = 9.80 m/s².
Result: 11.18 km/s, surface gravity 9.80 m/s²
Why the escaping object's mass does not matter
Escape velocity is derived by setting kinetic energy equal to the gravitational potential energy that must be overcome: ½mv² = GMm/r. The mass of the escaping object appears on both sides and cancels completely, leaving v = √(2GM/r), which depends only on the body being escaped.
So a pebble, a person and a fully fuelled rocket all need the same 11.18 km/s to leave Earth. What differs enormously is the energy required to reach that speed, since kinetic energy scales with mass — which is why launching a heavier payload costs more fuel even though the target speed is identical.
Escape velocity is not how rockets actually work
The figure describes an object given all its speed instantly at the surface and then coasting, like a cannonball. Real rockets do nothing of the sort: they accelerate continuously over minutes, gaining altitude as they go, and never travel at 11.18 km/s while still in the dense lower atmosphere — doing so would destroy them through drag heating.
Because gravity weakens with distance, a rocket that has already climbed needs less speed to escape from there. Continuous thrust means a rocket can leave Earth without ever reaching the surface escape velocity at any single moment. Escape velocity is a useful energy benchmark, not an operational requirement.
What escape velocity determines
It sets which gases a world can hold onto. Molecules in an atmosphere move at a range of speeds determined by temperature, and the lightest ones — hydrogen and helium — move fastest. Where escape velocity is low, those fast molecules gradually leak away over geological time.
This explains a good deal of the solar system. The Moon at 2.38 km/s retains essentially no atmosphere. Mars at 5.03 km/s holds only a thin one and has lost most of what it once had. Earth at 11.18 km/s retains nitrogen and oxygen comfortably but still loses hydrogen steadily. Jupiter at 59.5 km/s retains even hydrogen and helium, which is why it remains overwhelmingly composed of them.
The limiting case
Rearranging for radius shows that any mass compressed small enough produces an escape velocity equal to the speed of light. That radius is the Schwarzschild radius, and a body compressed within it is a black hole — nothing, including light, can escape.
Newtonian gravity breaks down well before that point and general relativity is required, which is why this calculator refuses rather than returning a Newtonian answer for such inputs. The Newtonian derivation nonetheless gives the correct Schwarzschild radius, a coincidence noted as early as 1783 by John Michell, long before relativity existed.
What this assumes, and where it stops
Assumptions
- The body is spherical with uniformly distributed mass, so gravity behaves as if all mass were at the centre.
- No atmospheric drag, and no gravitational influence from other bodies.
- Built-in bodies use equatorial radii, which is the convention published escape velocities follow. This matters for oblate bodies: Jupiter is about 6.5% flatter at the poles, and using its mean radius instead would give 60.2 km/s rather than the quoted 59.5.
Limitations
- Newtonian only. Near a black hole or any extremely compact object, general relativity is required and the calculator refuses rather than returning a wrong figure.
- Escape velocity assumes an instantaneous impulse at the surface. Real launches use continuous thrust and never need to reach this speed at ground level.
- G is the least precisely measured fundamental constant, with a relative uncertainty of about 2.2 × 10⁻⁵, which limits meaningful precision to roughly five significant figures.
- Ignores the rotation of the body, which gives a small assist to eastward launches — about 0.46 km/s at Earth's equator.
Common questions
Does a heavier rocket need a higher escape velocity?
No — escape velocity is identical for any mass, because the escaping object's mass cancels out of the derivation. What changes is the energy needed to reach that speed, which scales with mass. That is why heavier payloads cost more fuel despite needing the same target velocity.
Do rockets actually reach escape velocity?
Not at the surface, and usually not at all. Escape velocity assumes all the speed is delivered instantly at ground level and the object then coasts. Rockets thrust continuously while climbing, and since gravity weakens with altitude, they can escape without ever hitting 11.18 km/s in one moment. Travelling that fast in the lower atmosphere would in any case be destructive.
Why can the Moon not hold an atmosphere?
Its escape velocity of 2.38 km/s is too low. Gas molecules at any given temperature have a spread of speeds, and on a low-gravity body a meaningful fraction of them exceed escape velocity and drift away. Over geological time this strips the atmosphere entirely — the same process that thinned Mars's, and that still slowly removes hydrogen from Earth's.
Formula and content last reviewed on .
Results are estimates for information only, not professional advice.
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