Machining Cost Calculator (Cycle Time)

Work out cutting time, cycle time and cost per machined part, with tool life priced in through Taylor's equation and the economic cutting speed found.

How to use this calculator

  1. 1Total the cutting length across every pass on the part, then use the actual programmed feed rate.
  2. 2Be honest about non-cutting time. Rapids, tool changes and probing are often more of the cycle than cutting is.
  3. 3Enter tool life in minutes of cutting, not minutes of cycle - the distinction matters when cutting is a small share.
  4. 4Use a full shop rate that includes the machine, the operator and overhead. A labour-only rate understates what cycle time is worth.
  5. 5Compare the economic speed with what you run. Most shops sit below it.

How the calculation works

Cutting time = length of cut / feed rate Cycle = cutting + rapids + handling + (cutting / tool life) x change time Cost = cycle x rate + setup/batch x rate + (cutting / tool life) x tool cost Taylor: V x T^n = C Economic tool life: T = (1/n - 1) x (change time + tool cost / rate)
n
The Taylor exponent. About 0.125 for high speed steel, 0.25 for carbide, 0.5 for ceramic. Low n means life collapses fast as speed rises
T
Tool life in minutes of actual cutting, not minutes of cycle
Economic life
The life at which machine time saved by going faster exactly balances the cost of the tool changes it causes

The economic tool life depends only on the exponent, the tool change time and the tool cost expressed in minutes of shop rate. It does not depend on the part.

Because n is small for carbide, the speed-life relationship is steep: a 20% speed increase roughly halves the life.

The cost curve around the economic speed is quite flat, so being 10% off it costs very little. Being 50% off it costs a great deal.

Worked example

A settled production part

  1. 1.Cutting is 24 / 45 = 0.53 minutes. Add 0.5 of rapids and 1.0 of handling.
  2. 2.Each part uses 0.53/30 = 1.8% of a tool, so 0.053 minutes of tool change gets added: cycle is 2.09 minutes.
  3. 3.At $85/hr that is $2.96 of machine time, plus $0.85 of setup spread over 100 parts, plus $0.44 of tooling.
  4. 4.Total $4.25 a part, $425 for the batch. Cutting is only 26% of the cycle.

Result: $4.25 a part - and only a quarter of the cycle is cutting

The same part in a batch of five

  1. 1.Everything about the cut is identical - same cycle of 2.09 minutes, same tooling.
  2. 2.But the hour of setup now falls on five parts instead of a hundred: 12 minutes each.
  3. 3.That is $17.00 of setup against $0.85 before.
  4. 4.Cost per part goes from $4.25 to $20.40. Nothing about the machining changed; the batch size did all of it.

Result: $20.40 a part - setup is now 83% of the cost

A long cut where tooling starts to matter

  1. 1.Cutting is 600 / 20 = 30 minutes - one and a half tool lives per part.
  2. 2.So 1.5 tool changes per part: 6 minutes of changing and $60 of edges.
  3. 3.Cycle becomes 39 minutes; at $110/hr that is $71.50, plus $3.30 of setup, plus $60 of tooling.
  4. 4.Tooling is 44% of the $134.80 cost. When the share gets that high, the grade and the speed are worth revisiting together.

Result: $134.80 a part, with tooling at 44% of it

Finding the economic speed

  1. 1.Carbide has n = 0.25, so the economic tool life is (1/0.25 - 1) x (4 + 40/1.833) = 3 x 25.8 = 77.5 minutes.
  2. 2.That is longer than the 45 minutes this tool is getting, so the speed should come *down*, not up.
  3. 3.Taylor gives the speed for 77.5 minutes of life: 300 x (45/77.5)^0.25 = 262 sfm.
  4. 4.Running 300 sfm is past the balance point - the tool changes are costing more than the machine time they save.

Result: 262 sfm is economic; 300 is past the balance point

Cutting time is rarely the problem

The first surprise in any honest cycle time breakdown is how little of it involves metal being removed. On a typical prismatic part in a machining centre, cutting is often a quarter to a half of the cycle, and the rest is rapid moves, tool changes, probing, dwell, and the operator opening the door.

This has a direct consequence for where effort is worth spending. If cutting is 25% of the cycle, then making every cut instantaneous - which is not available - would improve the cycle by 25%. Meanwhile reducing the tool count by three, or fixturing two parts instead of one, can easily do better than that and costs nothing per part thereafter.

It is not an argument against getting feeds and speeds right; wrong ones break tools and scrap parts, which are expensive in their own way. It is an argument against treating cutting parameters as the main lever when they are usually the smaller one.

Taylor's equation and why speed is not free

In 1907 Frederick Taylor published the relationship that still governs this: cutting speed times tool life to some power is a constant. V x T^n = C. The exponent n depends on the tool material and is small - about 0.125 for high speed steel, 0.25 for carbide, 0.4 to 0.5 for ceramics.

A small exponent means a brutal trade. With carbide at n = 0.25, doubling the cutting speed divides tool life by two to the fourth power - a factor of sixteen. Even a modest 20% speed increase roughly halves the life. The relationship runs the other way too: slowing down 20% roughly doubles the life, which is why a struggling operation often improves dramatically from a small reduction.

This is also why the "just run it faster" instinct is dangerous with carbide specifically and much safer with high speed steel. At n = 0.125 the same doubling of speed costs a factor of 256 in life - high speed steel simply cannot be pushed, which is part of why it was displaced. But within its band it is far more forgiving of a wrong guess.

There is an economic speed, and most shops are below it

Going faster saves machine time and costs tool changes. Both are money, so somewhere the two curves cross and there is a speed that minimises cost per part.

The classical result is neat: the economic tool life depends only on the Taylor exponent, the time a tool change takes, and the cost of a cutting edge expressed in minutes of shop rate. T = (1/n - 1) x (change time + tool cost / rate). The part being made does not appear in it at all. For carbide at n = 0.25 that is three times the sum of the change time and the edge cost in minutes, which for typical numbers lands somewhere between 20 and 80 minutes of tool life.

Most shops run slower than that, and the reason is psychological rather than economic. A tool that wears out in fifteen minutes is visible, annoying and feels wasteful. A cycle that runs three minutes longer than it needs to is invisible. The cost of the second is usually larger.

The saving grace is that the cost curve near the optimum is flat. Being 10% off the economic speed costs almost nothing, which means precision here is not required - only avoiding being badly wrong in either direction.

Batch size does more than anything else

Setup is a fixed cost per batch, so its contribution per part is inversely proportional to the batch. That single fact dominates cost estimating for anything below a few hundred pieces.

A part with a two minute cycle and an hour of setup costs about three and a half dollars each in hundreds, and about twenty dollars each in fives. The machining is identical. Nothing about feeds, speeds, tooling or programming moved; only the divisor did.

It follows that for short runs, effort spent on setup reduction beats effort spent on cycle time by a wide margin - soft jaws that repeat, a fixture that locates without indicating, tool assemblies left preset. And it follows that quoting a short run at a long run's per-part price is one of the more reliable ways to lose money.

What this assumes, and where it stops

Assumptions

  • Tool life is entered as minutes of actual cutting, which is how tool life is normally measured and quoted.
  • Tool changes happen when the tool wears out rather than at programme boundaries, so a fractional tool change per part is charged.
  • Setup is a single fixed cost spread evenly over the batch.
  • The shop rate covers machine, operator and overhead together.
  • The Taylor exponent depends on the tool material only, which is the standard simplification.

Limitations

  • It costs one operation. A part with several very different cuts needs each estimated separately and added.
  • Scrap and rework are not included, and on a difficult part they can exceed the tooling cost.
  • Material cost is not included - this is the cost of machining, not the cost of the part.
  • The Taylor relation describes gradual wear. It says nothing about chipping, thermal cracking or a tool broken by a hard spot.
  • Programme structure, acceleration limits and lookahead all affect real cycle time and none are modelled.

Common questions

How do I calculate machining cycle time?

Cutting time is the total cut length divided by the feed rate. Add rapid moves, tool changes, probing and any dwell, then add loading and unloading. Cutting is usually a smaller share than people expect - often a quarter to a half of the cycle on a typical prismatic part.

What is Taylor's tool life equation?

V x T^n = C, where V is cutting speed, T is tool life in minutes of cutting, and n is an exponent set by the tool material - roughly 0.125 for high speed steel, 0.25 for carbide, 0.5 for ceramic. Because n is small, life falls very steeply as speed rises: 20% more speed roughly halves carbide tool life.

What is the economic cutting speed?

The speed at which the machine time saved by going faster exactly equals the cost of the extra tool changes. The optimum tool life works out as (1/n - 1) times the sum of the tool change time and the tool cost expressed in minutes of shop rate - and notably it does not depend on the part at all.

Why is my small batch so expensive per part?

Setup. It is a fixed cost divided by the batch size, so it doubles as the batch halves. A part with an hour of setup costs about $0.85 of setup each in hundreds and $17 each in fives. For short runs, reducing setup beats reducing cycle time by a very wide margin.

Should I run faster to reduce cost?

Usually yes, because most shops sit below the economic speed - a worn tool is visible and a slow cycle is not. But check rather than assume: if tooling is already a large share of the part cost, you are likely past the balance point already, and slowing down would be the cheaper move.

Sources

Formula and content last reviewed on .

Results are estimates for information only, not professional advice.

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