Voltage Drop Calculator
Calculate voltage drop over a cable run from length, size and current, and check it against the usual 3% and 5% limits.
How to use this calculator
- 1Enter the one-way distance to the load — the calculator accounts for the return path.
- 2Enter the load current and supply voltage.
- 3Compare against the 3% guideline for a final circuit, and use the size table to pick a conductor.
How the calculation works
R = ρL / A
Single-phase: Vdrop = 2 × I × R
Three-phase: Vdrop = √3 × I × R- ρ
- Resistivity — 1.724×10⁻⁸ Ω·m for copper, 2.826×10⁻⁸ for aluminium at 20 °C
- L
- One-way cable length in metres
- A
- Conductor cross-sectional area in square metres
- I
- Load current in amperes
Single-phase circuits use a factor of 2 because current flows out along one conductor and back along the other. Three-phase uses √3 because the return currents partly cancel.
Aluminium has about 64% higher resistivity than copper, so an aluminium conductor needs roughly 1.6× the cross-section for the same drop.
Resistivity rises with temperature by about 0.4% per °C for copper. A conductor at 70 °C has around 20% more resistance than at 20 °C, so real-world drop exceeds this calculation.
Worked example
16 A over 30 m of 2.5 mm² copper at 230 V
- 1.R = (1.724×10⁻⁸ × 30) ÷ (2.5×10⁻⁶) = 0.2069 Ω one way.
- 2.Single-phase doubles the conductor length: Vdrop = 2 × 16 × 0.2069 = 6.62 V.
- 3.As a percentage: 6.62 ÷ 230 = 2.88%.
- 4.Just inside the 3% guideline — but with no margin for the temperature rise in service.
Result: 6.62 V drop, 2.88% — marginally within the 3% guideline
Why voltage drops over a cable run
Every real conductor has some resistance, even though a wire is often treated as an "ideal" zero-resistance connection when sketching a circuit. That small resistance, spread over the length of a cable, consumes a bit of the supply voltage before it ever reaches the load — the longer or thinner the cable, the more of the original voltage is lost to it rather than delivered to whatever is plugged in at the far end.
This matters in practice because a motor, light or appliance is designed to run at a specific voltage. If too much of the supply is lost along the way, the device at the end of the run receives less than it needs — motors run hot and lose torque, older lighting dims, and sensitive electronics can behave unpredictably or fail to start at all.
What determines how much is lost
Cable resistance depends on three things: the material’s resistivity, how long the run is, and how thick the conductor is. Resistivity is a property of the metal itself — copper is a noticeably better conductor than aluminium, so a copper cable of a given size drops less voltage than an aluminium cable of the same size carrying the same current over the same distance. Aluminium is lighter and cheaper, which is why it remains common on long overhead and underground distribution runs despite needing a larger cross-section to match copper’s performance.
Length matters because resistance accumulates continuously along the conductor — twice the distance is, all else equal, twice the resistance and twice the voltage lost. Cross-sectional area works the other way: a thicker conductor gives current more room to flow, so resistance — and voltage drop — falls as area increases, roughly in inverse proportion.
Why single-phase and three-phase runs are calculated differently
Current does not just travel to a load — it also has to return to complete the circuit. In a single-phase or DC circuit, current goes out along one conductor and back along another, so the resistance it encounters is effectively double the one-way cable length. Three-phase circuits are arranged so the three phase currents partially cancel each other at the return path, which is why the standard voltage-drop formula for three-phase uses a factor of √3 — about 1.73 — rather than a flat 2.
This is also one reason three-phase power is often preferred for larger loads over long distances: for the same power delivered, three-phase wiring generally experiences less voltage drop and needs less conductor material than an equivalent single-phase run.
Where the 3% and 5% guidelines come from
Electrical codes in most countries do not typically mandate a hard voltage-drop limit as a safety rule the way they do for overcurrent protection, but both major wiring standards — the US National Electrical Code and the International Electrotechnical Commission’s guidance — converge on the same widely used recommendation: no more than roughly 3% drop on a final branch circuit, and no more than about 5% total from the service origin to the load. These figures are a design guideline for acceptable equipment performance, not an absolute physical limit.
Staying inside them is less about safety in the fire-risk sense and more about making sure connected equipment actually gets the voltage it was designed for. A cable sized only for current-carrying capacity can still satisfy a code’s ampacity rules while producing a voltage drop well outside these guidelines on a long run — exactly the kind of gap a voltage-drop check like this one is meant to catch.
What this assumes, and where it stops
Assumptions
- Conductors at 20 °C. In service they run hotter, increasing resistance and drop.
- A purely resistive load with unity power factor.
- Uniform cross-section along the whole run, with no joints.
Limitations
- Does not check current-carrying capacity, which is a separate and equally important constraint.
- Ignores grouping factors, ambient temperature, insulation type and installation method — all of which affect the permitted current.
- Reactive loads with a low power factor draw more current for the same power, increasing drop.
- Not a substitute for design to the applicable wiring regulations by a qualified electrician.
Common questions
What is an acceptable voltage drop?
The widely used guideline is 3% on a final circuit and 5% from the supply origin to the load overall. Beyond that, motors run hot, lighting dims, and electronics may behave unpredictably. Both IEC and NEC practice converge on these figures, though they are recommendations rather than absolute limits in most codes.
Why does the calculator double the cable length?
Because current has to return. In a single-phase or DC circuit it travels out along one conductor and back along the other, so it passes through twice the run length of copper. Three-phase circuits use a √3 factor instead, since the three return currents partly cancel each other.
Copper or aluminium?
Aluminium has about 64% higher resistivity, so it needs roughly 1.6 times the cross-sectional area for the same voltage drop. It is cheaper and lighter, which is why it dominates long distribution runs, but it needs different terminations and is not permitted for some applications.
Formula and content last reviewed on .
Results are estimates for information only, not professional advice.
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